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{\LARGE{
\hfil Math 120 A, B Winter 2013 \hfil \pp
\hfil Mid-Term Exam Number Two\hfil  \pp
\hfil February 28, 2013 \hfil \pp
\hfil Answers \hfil \pp
}}

\normalsize

There were two versions of the exam.

Version A - In problem 1, Robert walks 3 km/hr.

\begin{enumerate}

\item 1.14588 hours after 7 AM
\item 426.4328 years
\item (a) $f(10)=4.9277...$ (b) 0.036038... and 3.963961...
\item (a) $f(x) = -4+\sqrt{x-3}+\sqrt{x-4}$ (b) $\dsps f^{-1}(x) = 3+\left( \frac{-1-(x+4)^2}{-2(x+4)}\right)^2$
\end{enumerate}

Version B - In problem 1, Robert walks 2 km/hr.

\begin{enumerate}
\item 1.69371 hours after 7 AM
\item 182.128 years
\item  (a) $f(15) = 6.181818...$ (b) 0.13648... and $5.8635...$
\item (a) $ f(x) = -1+\sqrt{x+2}+\sqrt{x+1} $(b) $\dsps f^{-1}(x) = -2+\left(\frac{-1-(x+1)^2}{-2(x+1)}\right) ^2$
\end{enumerate}

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