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\noindent
\vfil \noindent
\large
\hfil Math 120 A, B - Winter 2009 \hfil \pp
\hfil Mid-Term Exam Number Two\hfil  \pp
\hfil February 26, 2009 \hfil \pp
\hfil Answers \hfil \pp
\normalsize

There were two versions of the exam.

\medskip

Version A - In problem 1, $g(x)=2x+x^2$.

\begin{enumerate}

\item 
\[
h^{-1}(x) = x+2-2\sqrt{x+1}.
\]

\item (a) $\dsps \frac{400}{13} = 30.769... $ feet (b) No.  The horizontal asymptote
of this function is $y=40$, and since the vertical asymptote is at $x=-10$, and
points on the function's graph to the right of $x=-10$ are below the asymptote, we can
conclude that Mr. X will never be able to jump over 40 feet.

\item (a) 58.528 m (b) 41.2105 sec

\item 17.36186 m

\end{enumerate}

Version B - In problem 1, $g(x) = 3x+x^2$.

\begin{enumerate}
\item 
\[
h^{-1}(x) = x+ \frac{9}{2} - \frac{1}{2} \sqrt{36x+81}.
\]

\item (a) 74 feet (b) No.  The horizontal asymptote
of this function is $y=90$, and since the vertical asymptote is at $x=-10$, and
points on the function's graph to the right of $x=-10$ are below the asymptote, we can
conclude that Mr. X will never be able to jump over 90 feet.

\item (a) 165.3806 m (b) 78.15789 sec

\item 19.3886 m

\end{enumerate}




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