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%\markboth{Dr. Matthew M. Conroy - University of Washington}{Dr. Matthew M. Conroy - University of Washington}


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{\LARGE{
\hfil Math 120 A, B Autumn 2012 \hfil \pp
\hfil Mid-Term Exam Number Two\hfil  \pp
\hfil November 15, 2012 \hfil \pp
\hfil Answers \hfil \pp
}}

There were two versions of the exam.

Version A: In problem 1, Maria heads toward the point $(15,12)$.

\begin{enumerate}
\item (a) $x=5t, y=4t$ (b) $x=8-2t, y=\frac{1}{2}t$ (c) $\frac{32}{35} $ seconds
\item 2 days from today
\item 40.5838 years after 2000
\item (a) $b(x)=3x-4$ (b) $g^{-1}(x)=\frac{4+x^2}{2x}, x \ge 2$ (c) $h(x)=\frac{2}{5} x$ is one 
solution
\end{enumerate}

Version B: In problem 1, Maria heads toward the point $(4,8)$.

\begin{enumerate}
\item (a) $x=2t, y=4t$ (b) $x=6-t, y=3t$ (c) $\frac{9}{5}$ second
\item $23.\bar{3}$ days from today
\item 34.915 years after 2000
\item (a) $b(x)=2x-4$ (b) $g^{-1}(x)=\frac{9+x^2}{2x}, x \ge 3$ (c) $h(x)=\frac{1}{18} x$ is
one solution
\end{enumerate}


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