Little
Given an isosceles triangle ABC, with |AB| = |AC| = b and |BC| = a, what is the radius R of the circumcircle of ABC? (The answer should be in terms of a and b, if possible.)
Suppose that D is a dilation with center O and ratio r (either r > 0 or r <0).
a) Prove that for any points A and B, that |D(A)D(B)| = |r| |AB|. Hint: Draw a figure.
b) If m is a line, prove that its image D(m) is either the line m itself (if O is on m) or is a line m' parallel to m.
c) If ABC is a triangle, prove that the triangle D(A)D(B)D(C) is similar to triangle ABC.
a) Suppose that S and T are isometries. Prove that the composition ST is also an isometry.
b) Suppose that M and N are line reflections, prove that MN is the inverse of NM.
Let m and n be parallel lines, distance d apart. Let M and N be the isometries that are reflection in m and n. Given points A and B, with A' = M(A) and B' = M(B) the reflections of these points in m and A'' = N(A') and B'' =N(B') be the reflections of A' and B' in n.
a) Prove that |AA''| = |BB''| = 2d. (You should check more than one case for A or B: the case points between m and n and the cases of points not between m and n.)
b) Show that AA''B''B is a parallelogram, provided that AB is not perpendicular to m and n.
c) Let p and q be two more lines parallel to m and n, with distance d from p to q. Denote by P and Q the line reflection transformation in p and in q. For any A, prove that either PQ(A) = MN(A) or QP(A) = MN(A).
d) From (b) and (c), prove that either PQ = MN or QP = MN. (Note: The hardest part of this proof is to figure out what the statements mean and then how one can check equality.)
a) Draw a picture and write a convincing explanation that on the number line, for two numbers a and b, the point m = (1/2) (a + b) is the midpoint of a and b.
b) Then for two points A = (a1, a2) and B = (b1, b2), find a formula for the midpoint M and explain why the formula is correct.
c) Then solve this equation for B to find the formula for the point reflection of A with center M.
d) If E = (e1, e2) and F = (f1, f2), then if HE is point reflection with center E and HF is point reflection with center F, then use (c) to find the formula for HEHF(x, y) for any point P = (x, y).